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Heterolysis of CH3CH2CH3 results in the ...

Heterolysis of `CH_3CH_2CH_3` results in the formation of

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B

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D

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To solve the question regarding the heterolysis of `CH3CH2CH3` (propane), we need to understand the concept of heterolysis and how it applies to the molecular structure of propane. ### Step-by-Step Solution: 1. **Identify the Compound**: The compound given is `CH3CH2CH3`, which is propane. It consists of three carbon atoms connected by single bonds. 2. **Understand Heterolysis**: Heterolysis refers to the breaking of a bond in such a way that both of the electrons from the bond are taken by one of the atoms involved in the bond. This results in the formation of a cation and an anion. 3. **Identify the Bond to Break**: In propane, we can consider the bond between the first carbon (`CH3`) and the second carbon (`CH2`). When this bond breaks, the electrons will be taken by the more electronegative atom, which in this case is the carbon atom that will become negatively charged. 4. **Draw the Products**: - When the bond between the first carbon (`CH3`) and the second carbon (`CH2`) breaks, the first carbon will take both electrons, resulting in a carbanion (`CH3^-`). - The second carbon, which is now positively charged due to the loss of the bond, will become a carbocation (`CH2^+`). 5. **Write the Final Products**: The heterolysis of propane results in the formation of: - A carbanion: `CH3^-` - A carbocation: `CH2^+` ### Final Answer: The heterolysis of `CH3CH2CH3` results in the formation of `CH3^-` (methyl anion) and `CH2^+` (ethyl cation). ---
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