Any ring system will be aromatic in nature if it possesses
I.Planarity
II.Complete delocalisation of the `pi` electron in the ring
III.It follows Huckle rule
Choose the correct option

Options

A. I and II
B. ii and III
C. I and IIII
D. All of the above

Answer

To determine whether a ring system is aromatic, we need to verify if it meets the following criteria:

1. **Planarity**: The ring must be planar, allowing for the overlap of p-orbitals. This is essential for the delocalization of π electrons across the ring.

2. **Complete Delocalization of π Electrons**: The π electrons in the ring must be fully delocalized. This means that the electrons are not confined to individual bonds but are spread out over the entire ring structure.

3. **Hückel's Rule**: The ring must contain a certain number of π electrons that follow Hückel's rule, which states that a molecule is aromatic if it has \(4n + 2\) π electrons, where \(n\) is a non-negative integer (0, 1, 2, ...).

Given these criteria, we can analyze the options:

- **I. Planarity**: This is a necessary condition for aromaticity. If the ring is not planar, the p-orbitals cannot overlap effectively, which is crucial for delocalization.

- **II. Complete Delocalization of π Electrons**: This is also essential. Without delocalization, the ring cannot exhibit aromatic character.

- **III. It follows Hückel's rule**: This is a defining criterion for aromaticity. The ring must have \(4n + 2\) π electrons to be considered aromatic.

Since all three conditions must be satisfied for a ring system to be aromatic, the correct answer is that all the options are necessary for aromaticity.

**Final Answer**: All of the above.