Identify the product Z in the following reaction scheme
`C_6H_5NH_2 overset (Ac_2O) rarr X overset (Br_2CCl_4) rarr Y overset (HOH) rarr Z`

Options

A. p- bromoaniline
B. P – bromoacetophenone
C. p- bromoacetanilide
D. O – bromoacetophenone

Answer

To identify the product Z in the given reaction scheme, we will analyze each step of the reaction:

1. **Starting Material**: The reaction begins with Aniline, which is represented by the chemical formula \( C_6H_5NH_2 \).

2. **First Reaction with Acetic Anhydride (\( Ac_2O \))**:
- Aniline reacts with acetic anhydride to form an acetanilide. The reaction can be represented as:
\[ C_6H_5NH_2 + (CH_3CO)_2O \rightarrow C_6H_5NHCOCH_3 + CH_3COOH \]
- Here, the amino group (-NH2) of Aniline is acetylated to form \( C_6H_5NHCOCH_3 \) (acetanilide). We denote this product as X.

3. **Second Reaction with Bromine in Carbon Tetrachloride (\( Br_2CCl_4 \))**:
- The acetanilide (X) then undergoes bromination in the presence of bromine and carbon tetrachloride. The bromination occurs primarily at the para position due to the electron-donating effect of the acetamido group (-NHCOCH3).
- The reaction can be represented as:
\[ C_6H_5NHCOCH_3 + Br_2 \rightarrow C_6H_4BrNHCOCH_3 + HBr \]
- This product, which is para-bromoacetanilide, is denoted as Y.

4. **Third Reaction with Water (\( HOH \))**:
- The final step involves hydrolysis of para-bromoacetanilide (Y) in the presence of water. During hydrolysis, the acetamido group is converted back to the amino group:
\[ C_6H_4BrNHCOCH_3 + H_2O \rightarrow C_6H_4BrNH_2 + CH_3COOH \]
- The product formed is para-bromoaniline, which is denoted as Z.

Thus, the final product Z is **para-bromoaniline**.

### Summary of Steps:
1. **Aniline** reacts with **Acetic Anhydride** to form **Acetanilide**.
2. **Acetanilide** is brominated to form **Para-Bromoacetanilide**.
3. **Para-Bromoacetanilide** is hydrolyzed to yield **Para-Bromoaniline**.