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In the following reaction,nHOOC(CH2)4COO...

In the following reaction,`nHOOC(CH_2)_4COOH+nH_2N(CH_2)_6 NH_2 overset(553 K)underset("High pressure")rarr`
The product is

A

B

C

D

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the reaction between adipic acid and hexamethylenediamine under high temperature and pressure conditions. This reaction is a classic example of the formation of a polymer through condensation. ### Step-by-Step Solution: 1. **Identify the Reactants**: - The first reactant is adipic acid, which has the formula HOOC(CH₂)₄COOH. This is a dicarboxylic acid. - The second reactant is hexamethylenediamine, which has the formula H₂N(CH₂)₆NH₂. This is a diamine. 2. **Understand the Reaction Conditions**: - The reaction occurs at a temperature of 553 K and under high pressure. These conditions favor the reaction and help drive the formation of the polymer. 3. **Determine the Type of Reaction**: - This is a condensation reaction where two molecules react to form a larger molecule (polymer) while eliminating water (H₂O) as a byproduct. 4. **Write the Reaction**: - The reaction can be represented as: \[ n \text{HOOC(CH}_2\text{)}_4\text{COOH} + n \text{H}_2\text{N(CH}_2\text{)}_6\text{NH}_2 \rightarrow \text{Polymer} + n \text{H}_2\text{O} \] 5. **Identify the Product**: - The product formed from this reaction is nylon-6,6. This polymer is formed by the alternating units of hexamethylenediamine and adipic acid. 6. **Draw the Structure of the Polymer**: - The repeating unit of nylon-6,6 can be represented as: \[ -\text{NH(CH}_2\text{)}_6\text{NHCO(CH}_2\text{)}_4\text{CO}- \] - This shows the amide linkages formed by the condensation of the carboxylic acid and amine groups. ### Final Answer: The product of the reaction is **nylon-6,6**. ---
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