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of 0.1 M NaOH solution is...

of 0.1 M NaOH solution is

A

9

B

11

C

10

D

10

Text Solution

Verified by Experts

The correct Answer is:
D
`underset("Strong base")(NaOH)rArrNa^(+)+OH^(-)`
`therefore[OH^(-)]` in 0.01 M NaOH solution= 0.01 M
`[H^(+)]=(Kw)/(OH^(-))=(1xx10^(-14))/(0.01)=1xx10^(-12)M`
`pH=-log[H^(+)]=-log[10^(-12)]`
`=-[-12log10]=+12`
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