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`(sintheta-costheta+1)/(sintheta+costheta-1)` (where `theta ne (pi)/(2))` is equal to

A

`(1)/(tan theta - sec theta)`

B

`(1)/(sec theta - tan theta)`

C

`(1)/(cos theta - tan theta)`

D

`(1)/(tan theta - cos theta)`

Text Solution

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The correct Answer is:
B
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