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If tantheta=(xsinphi)/(1-xcosphi)&tanphi...

If `tantheta=(xsinphi)/(1-xcosphi)&tanphi=(ysintheta)/(1-ycostheta)`, then `(x)/(y)=?`

A

`sin theta`

B

`sin phi`

C

`(1)/(sin phi)`

D

`(sin phi)/(sin phi)`

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The correct Answer is:
D
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