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On the head scale of any screw guage, th...

On the head scale of any screw guage, there are 50 divisions marked. If the thread difference of the screw is 1 mm then least count of screw guage will be

A

0.50 mm

B

0.02 mm

C

0.002 mm

D

0.05 mm

Text Solution

Verified by Experts

The correct Answer is:
C

Least count `= ("Thread difference")/("Number of divisions on head scale")`
`= (1)/(50) = 0.02 mm`
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Knowledge Check

  • The least count of a screw gauge is defined as

    A
    `"distance moved by thimble on main scale"/"number of rotation of thimble"`
    B
    `"pitch of the screw"/"number of divisions on circular scale"`
    C
    `"number of rotation of thimble"/"number of circular scale divisions"`
    D
    None of the above
  • Least count of screw gauge is defined as.

    A
    `("distance moved by thimble on main scale")/("number of rotation of thimble")`
    B
    `("pitch of the screw") /(" number of divisions on circular scale")`
    C
    `("number of rotation of thimble") /(" number of circular scale divisions")`
    D
    None of the above.
  • In a screw gauge, the main scale has divisions in millimetre and circular scale has 50 divisions. The least count of screw gauge is

    A
    `2` microns
    B
    `5` microns
    C
    `20` microns
    D
    `50` microns
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