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A body moving with uniform acceleration ...

A body moving with uniform acceleration `8 m//s^(2)` starts from rest. The distance covered by it in fifth second will be

A

8 m

B

64 m

C

4 m

D

36 m

Text Solution

Verified by Experts

The correct Answer is:
D
Distance travelled in 5s
`D_(5) = u(5) + (1)/(2)a (5)^(2)`
Distance travelled in 4s
`D_(4) = u(4) + (1)/(2)a(4)^(2)`
`D_(5) - D_(4) = u + (1)/(2)a xx 9`
`therefore` Distance travelled in 5th second
`= (1)/(2) a xx 9 = (1)/(2) xx 8 xx 9 = 36m`
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