Home
Class 12
PHYSICS
The displacement-time graph of a particl...

The displacement-time graph of a particle moving along a straight line is drawn below. The accelerations of the particle during the regions OP, PQ and QR are

A

OP = -, PQ = 0, QR = +

B

OP = +, PQ = 0, QR = +

C

OP = +, PQ = 0, QR = -

D

OP = -, PQ = 0, QR = -

Text Solution

Verified by Experts

The correct Answer is:
C

Acceleration `= (d^(2)x)/(d t^(2))`
For part OP, the acceleration is positive as the velocity is increasing, slope is increasing. For part PQ, the acceleration is zero. Horizontal straight line shows that the velocity is zero. For part QR, acceleration is negative. It is retarded motion. Velocity is decreasing as the slop decreases with time.
Promotional Banner

Similar Questions

Explore conceptually related problems

The distplcement time graph of a prticle moving alon a staraingt line is drawn below The acceleration of the paritcle during the regions OP, PQ and QR are

Displacement time graph of a particle moving in a straight line is a shown in figure.

Velocity versus displacement graph of a particle moving in a straight line as shown in figure. The acceleration of the particle.

The velocity –position graph of a particle moving along a straight line is shown. Then acceleration of the particle at s = 15 m is :

Velocity displacement graph of a particle moving in a straight line is as shown in figure.

The velocity -time (v - t) graph of a particle moving in a straight line is shown in figure. The acceleration of the particle at t = 9 is: