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The position x of a body is defined by e...

The position x of a body is defined by equation `x = Pt^(2) - Qt^(3)`. The acceleration of the particle will be zero at time equal to

A

`(P)/(Q)`

B

`(Q)/(P)`

C

`(P)/(3Q)`

D

`(3P)/(Q)`

Text Solution

Verified by Experts

The correct Answer is:
C
Acceleration `= (d^(2)x)/(d t^(2)) = (d(2Pt - 3Qt^(2)))/(d t) = 2P - 6Q t`
When a = 0 hence 2P - 6Q t = 0
`rArr t = 2P//6Q = (P)/(3Q)`
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