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The displacement of a particle along an ...

The displacement of a particle along an axis is described by equation `x = t^(3) - 6t^(2) + 12t + 1`. The velocity of particle when acceleration is zero, is

A

zero

B

`-6`

C

12

D

1

Text Solution

Verified by Experts

The correct Answer is:
A
Given, `x = t^(3) - 6t^(2) + 12t + 1`
Velocity `= (dx)/(d t) = 3t^(2) - 12t + 12`
Acceleration `= (d^(2)x)/(dt^(2)) = 6t - 12 = 0` (given)
`rArr t = (12)/(6) = 2`
`therefore` Velocity `= 3 xx (2)^(2) - 12 xx (2) + 12`
`= 12 - 24 + 12 = 0`
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