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An electron moving with velocity of 5 xx...

An electron moving with velocity of `5 xx 10^(4)` m/s. When it enters into an electric field, it gains an acceleration of `1 xx 10^(15)`. In how much time, velocity of electron will become double of initial velocity?

A

`5 xx 10^(-11)s`

B

`4 xx 10^(-11) s`

C

`3 xx 10^(-11)s`

D

`2 xx 10^(-11)s`

Text Solution

Verified by Experts

The correct Answer is:
A
According to the question,
`u = 5 xx 10^(4) m//s`
`a = 1 xx 10^(15) m//s^(2)`
`therefore` From, v = u + at,
`t = (v - u)/(a)`
`= (2u - u)/(a) = (u)/(a)`
`t = (5 xx 10^(4))/(10^(15))`
`= 5 xx 10^(-11)s`
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