On two like charge a repulsive force of 1.6 N is acting, when the distance between them is 0.04 m. If distance is changed to 0.02 m, then force between • them will be

Options

A. `2.3 N`
B. 4 N
C. `6.4 N`
D. `4.6 N`

Answer

C

Explanation

We know that `F prop (1)/(r^(2)) rArr (F_(2))/(F_(1))= ((r_(1))/(r_(2)))^(2)`
`(r_(1))/(r_(2))=(0.04)/(0.02)=2`
`:. (F_(2))/(F_(2))=(2)^(2)=4`
`:. F_(2)=F_(1)=1.6xx4=64N`