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A potential difference of 400 volt is ma...

A potential difference of 400 volt is maintained across a conductor of resistance 200 ohm. The number of electrons flowing through it in one second are `( e = 1 . 6 xx 10 ^(-19) C)`

A

` 4 . 0 xx 10 ^(19)`

B

`3 . 0 xx 10^(19)`

C

` 2 xx 10^(19)`

D

` 1 . 25 xx 10^(19)`

Text Solution

Verified by Experts

The correct Answer is:
B
Given, `V = 200 V, r = 200 Omega `
` e = 1 6 xx 10^(-19) C `
`l = (V)/(R) = (400)/( 200) = 2A `
Charge flowing in 1 s
` = 2 xx 1 = 2 C `
Therefore, the number of electrons flowing through the conductor in 1 s are
` n = (q)/( e) = (2)/( 1 . 6 xx 10^(-19)) = 1 . 25 xx 10 ^(19)`
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