if `theta = 45^0` then `tan^2 theta + 1/(sin^2 theta)`

If theta = 45^0 , then : (i) tan^2 theta + 1/(sin^2 theta) (ii) cos^2 theta - sin^2 theta

If theta=45^(@) then (tan^(2)theta-1)/(sec^(2)theta)=

Prove that : tan theta - cot theta = (2 sin^(2) theta - 1)/(sin theta cos theta)

Cosider the following : 1. tan ^(2) theta - sin ^(2) theta = tan ^(2) theta sin ^(2) theta 2. (cosec theta - sin theta ) (sec theta - cos theta ) (tan theta + cot theta ) =1 Which of the above is/are correct ?

The value of (sec^6 theta-tan^6 theta- 3 sec^2 theta tan^2 theta+1)/(cos^4 theta -sin^4 theta+2 sin^2 theta+2) is: (sec^6 theta-tan^6 theta- 3 sec^2 theta tan^2 theta+1)/(cos^4 theta -sin^4 theta+2 sin^2 theta+2) का मान क्या है ?

If sin theta=cos theta , then 2tan^(2)theta+sin^(2)theta-1= _____

If tan theta+1/(tan theta)=2 , then show that tan^(2)theta+1/(tan^(2)theta)= 0

Find the value मान ज्ञात करें : (sin theta+cos theta-1)/(sin theta-cos theta+1)xx(tan^2 theta (cosec^2 theta -1))/(sec theta -tan theta )