`tan^2 theta - sin^2 theta = ?`

tan theta . sin^2 theta = ?

If sec theta= a/b, b ne 0 , then (1-tan^2 theta)/(2-sin^2 theta) = ? यदि sec theta= a/b, b ne 0 , तो (1-tan^2 theta)/(2-sin^2 theta) = ?

The numerical value of 1/(1+cot^2 theta) + (3)/(1 + tan^2 theta) + 2 sin^2 theta will be

If theta = 45^0 , then : (i) tan^2 theta + 1/(sin^2 theta) (ii) cos^2 theta - sin^2 theta

If theta lies in the first quadrant and cos^2 theta - sin^2 theta = 1/2 then the value of tan^2 2 theta + sin^2 3 theta is:

Solve 3tan^(2) theta-2 sin theta=0 .

if theta = 45^0 then tan^2 theta + 1/(sin^2 theta)

3tan^(2)theta-2sin theta=0