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If theta = 45^0, then : (i) tan^2 theta...

If `theta = 45^0`, then :
(i) `tan^2 theta + 1/(sin^2 theta)`
(ii) `cos^2 theta - sin^2 theta`

Answer

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Knowledge Check

  • If tan theta = (12)/(13) , then (2 sin theta cos theta)/(cos^(2) theta - sin^(2) theta) is equal to

    A
    `(123)/(25)`
    B
    `(312)/(25)`
    C
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  • If (cos theta + i sin theta) ( cos 2 theta + i sin 2 theta).... (cosn theta + i sin theta) = 1, then the value of theta is

    A
    `(2 mpi)/(n ( n +1))`
    B
    `4 mpi`
    C
    `( 4 m pi)/( n ( n + 1))`
    D
    `( m pi )/( n( n+1))`

  • Consider the following (i) (cos^(2) theta - sin^(2) theta)/(cos^(2) theta + sin^(2) theta) = cos^(2) theta (1 + tan theta) (ii) (1 + sin theta)/(1 - sin theta) = (tan theta + sec theta)^(2) Which of the equation given above is/are correct ?

    A
    Only (i)
    B
    Only (ii)
    C
    Both (i) and (ii)
    D
    Neither (i) nor (ii)

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    ((sin theta-2 sin^3 theta)/(2 cos^3 theta- cos theta))^2-1, theta ne 45^@ , is equal to: ((sin theta-2 sin^3 theta)/(2 cos^3 theta- cos theta))^2-1, theta ne 45^@ का मान किसके बराबर है ?

    (sin5 theta-2sin3 theta + sin theta) / (cos5 theta-cos theta) = tan theta

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