If `HM:GM=4:5` for two positive numbers, then the ratio of two numbers is -

Let the harmonic mean and geometric mean of two positive numbers be in the ratio 4:5. Then the two numbers are in ratio

If the A.M. between two positive numbers exceeds their G.M. by 2 and the ratio of the numbers be 1: 4 find the numbers .

The difference between two whole numbers is 66. The ratio of the two numbers is 2 : 5. What are the two numbers?

Show that if A and G .are A.M. and G.M. between two positive numbers , then the numbers are A+- sqrt(A^(2) -G^(2))

The difference between two natural numbers is 196 and the ratio of the two numbers is 9:5. Find the two natural numbers.

If the ratio of H.M. and G.M. between two numbers a and b is 4:5 , then find the ratio of the two number ?

Statement 1 If a and b be two positive numbers, where agtb and 4xxGM=5xxHM for the numbers. Then, a=4b . Statement 2 (AM)(HM)=(GM)^(2) is true for positive numbers.

The AM of teo given positive numbers is 2. If the larger number is increased by 1, the GM of the numbers becomes equal to the AM to the given numbers. Then, the HM of the given numbers is

If A and G be A.M. and GM., respectively between two positive numbers, prove that the numbers are A+-sqrt((A+G)(A-G)) .

If A, G & H are respectively the A.M., G.M. & H.M. of three positive numbers a, b, & c, then equation whose roots are a, b, & c is given by