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On partial hydrolysis, XeF6 gives:...

On partial hydrolysis, `XeF_6` gives:

A

`XeO_(3) + 4HF`

B

`XeO_(2)F + HF`

C

`XeOF_(4) + H_(2)`

D

`XeO_(2)F_(2) + 4HF`

Text Solution

Verified by Experts

The correct Answer is:
D
`XeO_(2)F_(2) + 4HF`
`XeF_(4) + H_(2)O " "XeO_(2)F_(2) + 4HF`
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