Metal M ions form a ccp structure. Oxide ions occupy `1//2` octahedral and `1//2` tetrahedral voids. What is the formula of the oxide?

Options

A. MO
B. `MO_(2)`
C. `MO_(3)`
D. `M_(2)O_(3)`

Answer

D

Explanation

Metal M ions form ccp structure. Let number of ions of M be X
No of tetrahedral voids = 2x
No of octahedral voids = x
Number of oxide ions will be `(1)/(2) x + (1)/(2) (2x) = (3)/(2)x` Formula of oxide `= (M_(x)O_(3))/(2x) = M_(2) O_(3)`