`I_2` is only slightly soluble in

Options

A. `CHCl_3`
B. `H_2 O`
C. `C Cl_4`
D. `CS_2`

Explanation

To determine the solubility of iodine (I₂), we need to consider the nature of iodine and the types of solvents it interacts with.

### Step-by-Step Solution:

1. **Understanding Iodine (I₂)**:
- Iodine is a diatomic molecule consisting of two iodine atoms. It is a non-polar molecule due to its symmetrical linear structure.

2. **Types of Solvents**:
- Solvents can be broadly categorized into two types: polar and non-polar.
- **Polar Solvents**: These solvents have a significant dipole moment due to the presence of polar bonds (e.g., water, HF).
- **Non-Polar Solvents**: These solvents do not have a significant dipole moment and are typically composed of non-polar molecules (e.g., hexane, benzene).

3. **Solubility Principle**:
- The principle of "like dissolves like" states that polar solutes tend to dissolve in polar solvents, while non-polar solutes dissolve in non-polar solvents.

4. **Solubility of Iodine**:
- Since iodine (I₂) is non-polar, it is only slightly soluble in polar solvents (like water) and more soluble in non-polar solvents (like hexane or carbon tetrachloride).

5. **Conclusion**:
- I₂ is only slightly soluble in polar solvents and is more soluble in non-polar solvents.

### Final Answer:
I₂ is only slightly soluble in polar solvents (like water) and more soluble in non-polar solvents (like hexane).

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