Identify the chloronated product x formed when cyclo pentane reacts with chlorine in presence of sunlight.

Options

A. 1-pentene
B. 2-chloropentane
C. 1-chlorocyclopentane
D. 2-methyl butene

Explanation

To identify the chlorinated product \( X \) formed when cyclopentane reacts with chlorine in the presence of sunlight, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding the Reaction Conditions**:
- The reaction involves cyclopentane (\( C_5H_{10} \)) and chlorine (\( Cl_2 \)) in the presence of sunlight. Sunlight provides energy that initiates the reaction by generating chlorine radicals.

2. **Formation of Chlorine Radicals**:
- In the presence of sunlight, the \( Cl_2 \) molecule undergoes homolytic cleavage to form two chlorine radicals (\( Cl \cdot \)):
\[ Cl_2 \xrightarrow{h\nu} 2 Cl \cdot \]

3. **Initiation of the Reaction**:
- The chlorine radical (\( Cl \cdot \)) can abstract a hydrogen atom from cyclopentane, resulting in the formation of a cyclopentyl radical and hydrochloric acid (\( HCl \)):
\[ C_5H_{10} + Cl \cdot \rightarrow C_5H_9 \cdot + HCl \]
- Here, \( C_5H_9 \cdot \) is the cyclopentyl radical.

4. **Propagation Step**:
- The cyclopentyl radical can react with another chlorine radical to form the chlorinated product \( X \) (1-chlorocyclopentane) and regenerate another chlorine radical:
\[ C_5H_9 \cdot + Cl \cdot \rightarrow C_5H_9Cl + Cl \cdot \]
- The product formed is 1-chlorocyclopentane (\( C_5H_9Cl \)).

5. **Termination Step**:
- The reaction can terminate when two radicals combine to form a stable molecule, but in this case, we focus on the product formed:
\[ Cl \cdot + Cl \cdot \rightarrow Cl_2 \]
- This step is not necessary for identifying the product but is part of the radical reaction mechanism.

### Final Product:
- The chlorinated product \( X \) formed is 1-chlorocyclopentane.