Which one the following alcohol, gives alkenes most readily on acid-catalysed dehydration?

Options

A. `(CH_3)_3 COH`
B. `(CH_3)_2 CHCH_2 OH`
C. `CH_3 CHOHCH`
D. `CH_3 CH_2 CH_2 OH`

Explanation

To determine which alcohol gives alkenes most readily on acid-catalyzed dehydration, we need to analyze the stability of the carbocation formed during the dehydration process. The more stable the carbocation, the more readily it will form an alkene.

### Step-by-Step Solution:

1. **Understanding Acid-Catalyzed Dehydration**:
Acid-catalyzed dehydration involves the protonation of the alcohol to form a better leaving group (water), followed by the formation of a carbocation and the elimination of water to form an alkene.

2. **Identify the Alcohols**:
Let's consider the four options provided:
- Option 1: Tertiary alcohol (3°)
- Option 2: Secondary alcohol (2°)
- Option 3: Secondary alcohol (2°)
- Option 4: Primary alcohol (1°)

3. **Formation of Carbocations**:
- **Option 1 (Tertiary Alcohol)**: When the tertiary alcohol is protonated, it forms a tertiary carbocation, which is highly stable due to the +I effect of the three alkyl groups.
- **Option 2 (Secondary Alcohol)**: Protonation leads to a secondary carbocation, which is less stable than a tertiary carbocation.
- **Option 3 (Secondary Alcohol)**: Similar to option 2, this also forms a secondary carbocation.
- **Option 4 (Primary Alcohol)**: Protonation leads to a primary carbocation, which is the least stable of all carbocations.

4. **Comparing Stability**:
The stability of carbocations is ranked as follows:
- Tertiary (3°) > Secondary (2°) > Primary (1°)
Therefore, the tertiary carbocation formed from option 1 is the most stable.

5. **Conclusion**:
Since the tertiary alcohol (option 1) forms the most stable carbocation, it will dehydrate to form an alkene most readily compared to the other options.

### Final Answer:
**Option 1 (Tertiary alcohol) gives alkenes most readily on acid-catalyzed dehydration.**