`CH_3 CH= CH_2 to CH_3 CH_2 CH_2 OH` . Which reagent can be used for above convection .

Options

A. `O_3//Zn`
B. Oxmium tetroxide `(O_7 O_4//CH_2 Cl_2)`
C. `B_2 H_6 and ` alk. `H_2 O_2`
D. `O_2//Zn`

Explanation

To convert the compound CH₃CH=CH₂ (propene) to CH₃CH₂CH₂OH (1-propanol), we can use a two-step process involving diborane (B₂H₆) followed by oxidation. Here’s a step-by-step solution:

### Step 1: Hydroboration
1. **Reagent Used**: Diborane (B₂H₆)
- When propene (CH₃CH=CH₂) reacts with diborane, it undergoes hydroboration. In this reaction, diborane adds across the double bond of propene.
- The product formed is trialkylborane, specifically tri-n-propylborane (CH₃CH₂CH₂O-B(OR)₃).

### Step 2: Oxidation
2. **Reagent Used**: Hydrogen peroxide (H₂O₂) in the presence of a base (usually NaOH)
- The trialkylborane formed in the first step is then treated with hydrogen peroxide and a base. This step oxidizes the boron compound to form the corresponding alcohol.
- The final product is 1-propanol (CH₃CH₂CH₂OH).

### Overall Reaction
The overall reaction can be summarized as:
1. CH₃CH=CH₂ + B₂H₆ → CH₃CH₂CH₂B(OR)₃ (trialkylborane)
2. CH₃CH₂CH₂B(OR)₃ + H₂O₂/NaOH → CH₃CH₂CH₂OH + B(OH)₃

Thus, the reagent that can be used for the conversion of CH₃CH=CH₂ to CH₃CH₂CH₂OH is **diborane (B₂H₆)** followed by **hydrogen peroxide (H₂O₂)**.