Divide 56 in four parts in A.P. such that the ratio of the product of their extremes (1st and 4th) to the product of means (2nd and 3rd) is 5:6.

Divide 32 into four parts which are in A.P.such that the ratio of the product of extremes to the product of means is 7:15.

Divide 56 into four parts which are in A.P. such that the ratio of product of extremes to the product of means is 5:6 .

Divide 28 into four parts in an A.P.so that the ratio of the product of first and third with the product of second and fourth is 8:15.

Divide 32 into four parts which are in A.P.such that the product of extremes is to the product of means is 7:15.

Divide 32 into four parts which are in A.P.such that the product of extremes is to the product of means is 7:15.

Divide 20 into four parts which are in A.P. and such that the product of the first and fourth is to the product of the second and third in the ratio 2:3 . Find the products of the first and fourth term of the A.P. :

Four parts of 24 are in A.P. such that the ratio of product of extremes to products of means is 7:15 , then four parts are

Find four consecutive terms in an A.P. Whose sum is 72 and the ratio of the product of the 1st and the 4th terms to the product of the 2nd and 3rd terms is 9 : 10. (a) Let the four consecutive terms be a - 3d, a - d, a + d, a + 3d. (b) Using the first condition, find the value of a. (c) Using the second condition, find the value of d and hence the numbers.

4.(a) Divide 20 into 4 parts which are in A.P. and such that.the product of the first and fourth is to the product o the secondi.and third in the ratio 2:3.

Divide 124 into four parts in such a way that they are in AP and the product of the first and the 4 th part is 128 less than the product of the 2nd and the 3 rd parts.