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The sum of exponents of prime factors in...

The sum of exponents of prime factors in the prime -factorisation of 196 is

A

3

B

4

C

5

D

6

Text Solution

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The correct Answer is:
To find the sum of the exponents of the prime factors in the prime factorization of 196, we can follow these steps: ### Step 1: Prime Factorization of 196 To begin, we need to factor 196 into its prime factors. 1. Start with the number 196. 2. Divide by the smallest prime number, which is 2. - \( 196 \div 2 = 98 \) 3. Now, factor 98. - \( 98 \div 2 = 49 \) 4. Next, factor 49. - \( 49 \div 7 = 7 \) 5. Finally, factor 7. - \( 7 \div 7 = 1 \) So, the complete factorization of 196 is: \[ 196 = 2^2 \times 7^2 \] ### Step 2: Identify the Exponents From the prime factorization, we can see the exponents of the prime factors: - The exponent of 2 is 2. - The exponent of 7 is 2. ### Step 3: Sum the Exponents Now, we sum the exponents of the prime factors: \[ 2 + 2 = 4 \] ### Final Answer The sum of the exponents of the prime factors in the prime factorization of 196 is **4**. ---
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The sum of the exponents of the prime factors in the prime factorisation of 196, is (a) 1 (b) 2 (c) 4 (d) 6

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Knowledge Check

  • What is the sum of exponents of prime factors in the prime factorisation of 250.

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    B
    6
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    8
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  • Write the sum of exponents of prime factors in the prime factorisation of 250.

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  • The prime factorisation of 640 is:

    A
    `2 xx 2 xx 2 xx 2 xx 2 xx5`
    B
    `2 xx 2 xx 2 xx 2 xx 2 xx 2 xx 5`
    C
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    D
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