Home
Class 10
MATHS
Find HCF and LCM of 404 and 96 and verif...

Find HCF and LCM of 404 and 96 and verify that `HCF times LCM `=Product of the two given numbers

Text Solution

AI Generated Solution

The correct Answer is:
To find the HCF (Highest Common Factor) and LCM (Lowest Common Multiple) of the numbers 404 and 96, and to verify that HCF × LCM = Product of the two numbers, we can follow these steps: ### Step 1: Prime Factorization of 404 To find the prime factorization of 404: - 404 is even, so we divide by 2: \[ 404 \div 2 = 202 \] - 202 is also even, so we divide by 2 again: \[ 202 \div 2 = 101 \] - 101 is a prime number. Thus, the prime factorization of 404 is: \[ 404 = 2^2 \times 101^1 \] ### Step 2: Prime Factorization of 96 Now, we find the prime factorization of 96: - 96 is even, so we divide by 2: \[ 96 \div 2 = 48 \] - 48 is even, so we divide by 2 again: \[ 48 \div 2 = 24 \] - 24 is even, so we divide by 2 again: \[ 24 \div 2 = 12 \] - 12 is even, so we divide by 2 again: \[ 12 \div 2 = 6 \] - 6 is even, so we divide by 2 again: \[ 6 \div 2 = 3 \] - 3 is a prime number. Thus, the prime factorization of 96 is: \[ 96 = 2^5 \times 3^1 \] ### Step 3: Finding HCF To find the HCF, we take the lowest power of each common prime factor: - For the prime factor 2: The minimum power is \(2^2\). - For the prime factor 101: It is not common in 96. - For the prime factor 3: It is not common in 404. Thus, the HCF is: \[ HCF = 2^2 = 4 \] ### Step 4: Finding LCM To find the LCM, we take the highest power of each prime factor: - For the prime factor 2: The maximum power is \(2^5\). - For the prime factor 101: The maximum power is \(101^1\). - For the prime factor 3: The maximum power is \(3^1\). Thus, the LCM is: \[ LCM = 2^5 \times 3^1 \times 101^1 \] Calculating this: \[ = 32 \times 3 \times 101 \] \[ = 96 \times 101 = 9696 \] ### Step 5: Verification Now we verify that HCF × LCM = Product of the two numbers: - HCF = 4 - LCM = 9696 - Product of the two numbers = 404 × 96 Calculating the product: \[ 404 \times 96 = 38784 \] Now, calculating HCF × LCM: \[ 4 \times 9696 = 38784 \] Since both sides are equal: \[ HCF \times LCM = Product \text{ of the two numbers} \] Thus, the verification is complete. ### Final Results - HCF = 4 - LCM = 9696
Promotional Banner

Topper's Solved these Questions

  • REAL NUMBERS

    EDUCART PUBLICATION|Exercise LONG QUESTION TYPE QUESTIONS|5 Videos
  • REAL NUMBERS

    EDUCART PUBLICATION|Exercise SHORT QUESTION (SA-I) TYPE QUESTIONS|12 Videos
  • QUADRATIC EQUATIONS

    EDUCART PUBLICATION|Exercise LONG ANSWER Type Questions [4 marks]|19 Videos
  • SAMPLE PAPER - 6

    EDUCART PUBLICATION|Exercise PART - B (SECTION - IV)|13 Videos

Similar Questions

Explore conceptually related problems

Find HCF and LCM of 404 and 96 and verify that HCF xx LCM= product of the two given numbers

Find HCF and LCM of 404 and 96 and verify that HCF xx LCM = Product of two given numbers .

Find the LCM and HCF of the 26 and 91 and verify that HCF xx LCM = product of the given two numbers.

Using prime factorisation find HCF and LCM of 18,45 and 60 check if HCF x LCM = product of the number

find the HCF and LCM of 30, 72 and 108. Also show that HCF xx LCM ne Product of the three numbers

Find the LCM and HCF of the following pair of integers and verify that LCM xx HCF = Product of the two numbers 26 and 91

Find the LCM and HCF of the following pair of integers and verify that LCM xx HCF = Product of the two numbers 510 and 92

Find the LCM and HCF of the following pair of integers and verify that LCM xx HCF = Product of the two numbers 336 and 54

Using prime factorisation method, find the HCF and LCM of the following pairs. Hence, verify HCF xx LCM = product of two numbers. (i) 96 and 120 (ii) 16 and 20 (iii) 144 and 192 (iv) 330 and 440

Find the LCM and HCF of the following pairs of integers and verify that L.L CM xx HCF= product of the two numbers.(i) 26 and 91 (ii) 510 and 92 (iii) 336 and 54