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Let ABC ~ triangle DEF and their areas b...

Let `ABC ~ triangle DEF` and their areas be `81 cm^(2)` and `144 cm^(2)`. If EF = 24 cm, then length of side BC is ……………………. Cm

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To find the length of side BC in triangle ABC given that triangle ABC is similar to triangle DEF, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the relationship between the areas of similar triangles**: The ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides. \[ \frac{\text{Area of } ABC}{\text{Area of } DEF} = \left(\frac{BC}{EF}\right)^2 \] 2. **Substitute the given areas**: We know the areas of triangles ABC and DEF: \[ \frac{81 \, \text{cm}^2}{144 \, \text{cm}^2} = \left(\frac{BC}{24 \, \text{cm}}\right)^2 \] 3. **Simplify the area ratio**: Simplifying \(\frac{81}{144}\): \[ \frac{81}{144} = \frac{9}{16} \] So we have: \[ \frac{9}{16} = \left(\frac{BC}{24}\right)^2 \] 4. **Take the square root of both sides**: Taking the square root gives us: \[ \frac{3}{4} = \frac{BC}{24} \] 5. **Cross-multiply to solve for BC**: Cross-multiplying gives: \[ 3 \times 24 = 4 \times BC \] \[ 72 = 4 \times BC \] 6. **Divide by 4**: To isolate BC, divide both sides by 4: \[ BC = \frac{72}{4} = 18 \, \text{cm} \] ### Final Answer: The length of side BC is **18 cm**. ---
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