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A metallic sphere of diameter 20 cm is r...

A metallic sphere of diameter 20 cm is recast into a right circular cone of base radius 10 cm. What is the bigger height of the cone ?

A

4 cm

B

40 cm

C

60 cm

D

120 cm

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the height of a right circular cone that is formed by recasting a metallic sphere. We will follow these steps: ### Step 1: Calculate the volume of the sphere The formula for the volume \( V \) of a sphere is given by: \[ V = \frac{4}{3} \pi r^3 \] where \( r \) is the radius of the sphere. Given the diameter of the sphere is 20 cm, the radius \( r \) is: \[ r = \frac{20}{2} = 10 \text{ cm} \] Now, substituting the radius into the volume formula: \[ V = \frac{4}{3} \pi (10)^3 = \frac{4}{3} \pi (1000) = \frac{4000}{3} \pi \text{ cm}^3 \] ### Step 2: Calculate the volume of the cone The formula for the volume \( V \) of a cone is given by: \[ V = \frac{1}{3} \pi r^2 h \] where \( r \) is the radius of the base and \( h \) is the height of the cone. Given the base radius of the cone is 10 cm, we can substitute this into the volume formula: \[ V = \frac{1}{3} \pi (10)^2 h = \frac{1}{3} \pi (100) h = \frac{100}{3} \pi h \text{ cm}^3 \] ### Step 3: Set the volumes equal Since the sphere is recast into the cone, their volumes are equal: \[ \frac{4000}{3} \pi = \frac{100}{3} \pi h \] ### Step 4: Solve for height \( h \) We can cancel \( \pi \) from both sides: \[ \frac{4000}{3} = \frac{100}{3} h \] Now, multiply both sides by 3 to eliminate the fraction: \[ 4000 = 100h \] Now, divide both sides by 100: \[ h = \frac{4000}{100} = 40 \text{ cm} \] ### Conclusion The height of the cone is \( 40 \) cm. ---
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