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A train covered a certain distance at a uniform speed. If the train would have been 6 m/hr. faster, it would have taken 4 hours less than the scheduled time and if the train would have slowed down by 6 km/hr, it would have taken 6 hours more than scheduled time. Find the length of the journey.

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To solve the problem step by step, we will define the variables and set up the equations based on the information provided in the question. ### Step 1: Define Variables Let: - \( x \) = speed of the train in km/hr - \( y \) = time taken to cover the distance in hours ### Step 2: Write the Distance Formula The distance covered by the train can be expressed as: \[ \text{Distance} = \text{Speed} \times \text{Time} = x \cdot y \] ### Step 3: Set Up the First Condition According to the first condition, if the speed increases by 6 km/hr, the time taken decreases by 4 hours. This gives us the equation: \[ \text{New Speed} = x + 6 \quad \text{and} \quad \text{New Time} = y - 4 \] So, the distance can also be expressed as: \[ x \cdot y = (x + 6)(y - 4) \] Expanding the right side: \[ xy = xy - 4x + 6y - 24 \] Cancelling \( xy \) from both sides: \[ 0 = -4x + 6y - 24 \] Rearranging gives us: \[ 4x - 6y = -24 \quad \text{(Equation 1)} \] ### Step 4: Set Up the Second Condition According to the second condition, if the speed decreases by 6 km/hr, the time taken increases by 6 hours. This gives us the equation: \[ \text{New Speed} = x - 6 \quad \text{and} \quad \text{New Time} = y + 6 \] So, the distance can also be expressed as: \[ x \cdot y = (x - 6)(y + 6) \] Expanding the right side: \[ xy = xy + 6x - 6y - 36 \] Cancelling \( xy \) from both sides: \[ 0 = 6x - 6y - 36 \] Rearranging gives us: \[ 6x - 6y = 36 \quad \text{(Equation 2)} \] ### Step 5: Simplify the Equations From Equation 1: \[ 2x - 3y = -12 \quad \text{(Dividing by 2)} \] From Equation 2: \[ x - y = 6 \quad \text{(Dividing by 6)} \] ### Step 6: Solve the System of Equations Now we have: 1. \( 2x - 3y = -12 \) 2. \( x - y = 6 \) From the second equation, we can express \( x \) in terms of \( y \): \[ x = y + 6 \] Substituting this into the first equation: \[ 2(y + 6) - 3y = -12 \] Expanding: \[ 2y + 12 - 3y = -12 \] Combining like terms: \[ -y + 12 = -12 \] Subtracting 12 from both sides: \[ -y = -24 \] Thus, we find: \[ y = 24 \] ### Step 7: Find \( x \) Substituting \( y = 24 \) back into the equation \( x - y = 6 \): \[ x - 24 = 6 \] So: \[ x = 30 \] ### Step 8: Calculate the Distance Now we can find the distance: \[ \text{Distance} = x \cdot y = 30 \cdot 24 = 720 \text{ km} \] ### Final Answer The length of the journey is: \[ \boxed{720 \text{ km}} \]
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