Home
Class 10
MATHS
If P(E) = 0.005, then find the probabili...

If P(E) = 0.005, then find the probability of ''not E'.

Text Solution

AI Generated Solution

The correct Answer is:
To find the probability of "not E" given that P(E) = 0.005, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the relationship between P(E) and P(not E)**: The probability of an event and the probability of its complement (not the event) always add up to 1. This can be expressed as: \[ P(E) + P(\text{not } E) = 1 \] 2. **Substitute the known value**: We know that P(E) = 0.005. We can substitute this value into the equation: \[ 0.005 + P(\text{not } E) = 1 \] 3. **Solve for P(not E)**: To find P(not E), we need to isolate it on one side of the equation. We can do this by subtracting P(E) from both sides: \[ P(\text{not } E) = 1 - 0.005 \] 4. **Calculate the result**: Now, perform the subtraction: \[ P(\text{not } E) = 1 - 0.005 = 0.995 \] 5. **Final Answer**: Therefore, the probability of "not E" is: \[ P(\text{not } E) = 0.995 \]
Promotional Banner

Similar Questions

Explore conceptually related problems

If P(E)=0.05, what is the probability of not E?

If P(E )=0.75 , what is the probability of 'not E'?

If P(E) = 0.001, then find the value of P(vecE) .

If P(E)=0.73 then the probability of E not not happening is

Let n be the number of trials that an event E occurred and m be the total number of trials, then find the probability of the event E.

If P(E) = 0.34, find p(not E).

If P (E) denotes the probability of an event E, then:

If P(E) denotes the probability of an event E then (a) 0 lt P(E) le 1 (b) 0 lt P(E) lt 1 (c) 0 le P(E) le 1 (d) 0 le P(E) lt 1