Home
Class 10
MATHS
Using prime factorisation, find the HCF ...

Using prime factorisation, find the HCF and LCM of 150 and 240.

Text Solution

AI Generated Solution

The correct Answer is:
To find the HCF (Highest Common Factor) and LCM (Lowest Common Multiple) of the numbers 150 and 240 using prime factorization, we will follow these steps: ### Step 1: Prime Factorization of 150 To find the prime factorization of 150, we divide it by the smallest prime numbers until we reach 1. 1. Divide by 2: \( 150 \div 2 = 75 \) So, we have \( 150 = 2 \times 75 \). 2. Divide by 3: \( 75 \div 3 = 25 \) So, \( 75 = 3 \times 25 \). Thus, \( 150 = 2 \times 3 \times 25 \). 3. Divide by 5: \( 25 \div 5 = 5 \) So, \( 25 = 5 \times 5 \). Thus, \( 150 = 2 \times 3 \times 5 \times 5 \). The prime factorization of 150 is: \[ 150 = 2^1 \times 3^1 \times 5^2 \] ### Step 2: Prime Factorization of 240 Next, we perform the same process for 240. 1. Divide by 2: \( 240 \div 2 = 120 \) So, \( 240 = 2 \times 120 \). 2. Divide by 2 again: \( 120 \div 2 = 60 \) So, \( 120 = 2 \times 60 \). Thus, \( 240 = 2^2 \times 60 \). 3. Divide by 2 again: \( 60 \div 2 = 30 \) So, \( 60 = 2 \times 30 \). Thus, \( 240 = 2^3 \times 30 \). 4. Divide by 2 again: \( 30 \div 2 = 15 \) So, \( 30 = 2 \times 15 \). Thus, \( 240 = 2^4 \times 15 \). 5. Divide by 3: \( 15 \div 3 = 5 \) So, \( 15 = 3 \times 5 \). Thus, \( 240 = 2^4 \times 3^1 \times 5^1 \). The prime factorization of 240 is: \[ 240 = 2^4 \times 3^1 \times 5^1 \] ### Step 3: Finding HCF To find the HCF, we take the lowest power of each common prime factor from both factorizations. - For \( 2 \): The minimum power is \( 2^1 \). - For \( 3 \): The minimum power is \( 3^1 \). - For \( 5 \): The minimum power is \( 5^1 \). Thus, the HCF is: \[ HCF = 2^1 \times 3^1 \times 5^1 = 2 \times 3 \times 5 = 30 \] ### Step 4: Finding LCM To find the LCM, we take the highest power of each prime factor from both factorizations. - For \( 2 \): The maximum power is \( 2^4 \). - For \( 3 \): The maximum power is \( 3^1 \). - For \( 5 \): The maximum power is \( 5^2 \). Thus, the LCM is: \[ LCM = 2^4 \times 3^1 \times 5^2 = 16 \times 3 \times 25 \] Calculating this step by step: 1. \( 16 \times 3 = 48 \) 2. \( 48 \times 25 = 1200 \) So, the LCM is: \[ LCM = 1200 \] ### Final Answers - HCF of 150 and 240 is **30**. - LCM of 150 and 240 is **1200**. ---
Promotional Banner

Similar Questions

Explore conceptually related problems

Using prime factorisation, find HCF and LCM of 18, 45 and 60.

Using prime factorisation method, find the HCF and LCM of 210 and 175

Using prime factorisation method, find the HCF and LCM of 210 and 175.

Using prime factorisation , find the LCM of 150 and 210.

Using prime factorisation find HCF and LCM of 18,45 and 60 check if HCF x LCM = product of the number

Using prime factorisation, find the LCM of 150 and 210.

Using prime factorisation, find the LCM of 90 and 120.

Using prime factorization method find the HCF and LCM of 72,126 and 168. Also show that HCF x LCM is not equal to the product of the three numbers

Using prime factorisation method, find the HCF and LCM of the following pairs. Hence, verify HCF xx LCM = product of two numbers. (i) 96 and 120 (ii) 16 and 20 (iii) 144 and 192 (iv) 330 and 440