Home
Class 10
MATHS
The diagonal BD of a parallelogram ABCD ...

The diagonal BD of a parallelogram ABCD intersects the segment AE at the point F, where E is any point on the Side BC. Prove that `DFxxEF= FBxxFA`.

Text Solution

Verified by Experts

The correct Answer is:
`DFxxEF=FBxxFA`
Promotional Banner

Similar Questions

Explore conceptually related problems

The diagonal BD of a parallelogram ABCD intersects the segment AE at the point F where E is any point on the side BC. Prove that DFxEF=FBxFA

diagonal of a cocyclic parallelogram ABCD is AC and BD intersection at point R .then

The diagonals AC and BD of a parallelogram ABCD intersect each other at the point O. If angleDAC=32^(@) and angleAOB=70^(@) , then angleDBC is equal to

In rectangle ABCD, E is the midpoint of side BC. Prove that, AE = DE.

The diagonals AC and BD of a parallelogram ABCD intersect each other at the point O. If angle DAC = 32^(@) and angle AOB =70^(@), " find " angle DBC.

In parallelogram ABCD,E is the mid-point of AD and F is the mid-point of BC.Prove that BFDE is a parallelogram.

Given Parallelogram ABCD in which diagonals AC and BD at M.Prove M is mid-point of LN.

E and F are points on diagonal AC of a parallelogram ABCD such that AE=CF. Show that BFDE is a parallelogram.

Point E and F lie on diagonals AC of a parallelogram ABCD such that AE=CF What type of quadrilateral is BFDE?