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If triangleABC - trianglePQR and (BC)/(Q...

If `triangle`ABC - `triangle`PQR and `(BC)/(QR)` = `1/4` then `(ar(trianglePQR))/(ar(triangleABC))` =

A

`1/4`

B

`4/1`

C

`1/16`

D

`16/1`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the ratio of the areas of two similar triangles, triangle ABC and triangle PQR, given that the ratio of the lengths of the corresponding sides BC and QR is \( \frac{1}{4} \). ### Step-by-Step Solution: 1. **Understanding Similar Triangles**: Since triangle ABC is similar to triangle PQR, the ratio of their corresponding sides is equal. This means that if we know the ratio of one pair of corresponding sides, we can use it to find the ratio of their areas. **Hint**: Remember that similar triangles have proportional sides. 2. **Given Ratio of Sides**: We are given that \( \frac{BC}{QR} = \frac{1}{4} \). Here, BC is a side of triangle ABC, and QR is the corresponding side of triangle PQR. **Hint**: Identify the corresponding sides in similar triangles. 3. **Finding the Inverse Ratio**: To find the ratio of QR to BC, we take the reciprocal of the given ratio: \[ \frac{QR}{BC} = \frac{1}{\frac{1}{4}} = 4 \] **Hint**: When dealing with ratios, the inverse can be useful for finding corresponding relationships. 4. **Using the Area Ratio Theorem**: The area of similar triangles is proportional to the square of the ratio of their corresponding sides. Therefore, we can express the ratio of the areas as: \[ \frac{ar(\triangle PQR)}{ar(\triangle ABC)} = \left(\frac{QR}{BC}\right)^2 \] **Hint**: Recall the theorem that states the area ratio is the square of the side ratio. 5. **Substituting the Ratio**: Now we substitute the value we found for \( \frac{QR}{BC} \): \[ \frac{ar(\triangle PQR)}{ar(\triangle ABC)} = \left(4\right)^2 = 16 \] **Hint**: Make sure to square the ratio when calculating area ratios. 6. **Final Answer**: Thus, the ratio of the area of triangle PQR to the area of triangle ABC is: \[ \frac{ar(\triangle PQR)}{ar(\triangle ABC)} = 16 \] ### Conclusion: The final answer is \( \frac{ar(\triangle PQR)}{ar(\triangle ABC)} = 16 \).
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triangle ABC ~ triangle RQP and PQ =10 cm, QR = 12 cm and RP = 16 cm. If ar(triangle PQR) :ar(triangle ABC) =9/4 , then BC is equal to: triangle ABC ~ triangle RQP है और PQ = 10cm, QR = 12 cm तथा RP = 16 cm है । यदि ar(triangle PQR) :ar(triangle ABC) =9/4 है, तो BC का मान किसके बराबर होगा ?

Let triangle ABC~ triangle QPR and (ar(triangle ABC))/(ar(triangle PQR))=4/25 . If AB = 12cm BC = 8cm AC = 10cm, then QR is equal to: माना कि triangle ABC~ triangle QPR और (ar(triangle ABC))/(ar(triangle PQR))= 4/25 है| यदि AB = 12cm BC = 8cm AC = 10cm है तो QR बराबर है:

Let triangle ABC ~ triangle RPQ and (ar(triangle ABC))/(ar(triangle PQR))= 4/9 , If AB = 3cm, BC=4cm and AC = 5cm, then PQ (in cm ) is equal to : मान लीजिये कि triangle ABC ~ triangle RPQ तथा (ar(triangle ABC))/(ar(triangle PQR))= 4/9 हैं | यदि AB = 3cm, BC=4cm और AC = 5cm है, तो PQ का मान ज्ञात करे:

Let triangle ABC ~ triangle RPQ and (ar(triangle ABC))/(ar(triangle PQR))= 4/9 , If AB = 3cm, BC=4cm and AC = 5cm, then RP (in cm ) is equal to : मान लीजिये कि triangle ABC ~ triangle RPQ तथा (ar(triangle ABC))/(ar(triangle PQR))= 4/9 हैं | यदि AB = 3cm, BC=4cm और AC = 5cm है, तो RP का मान ज्ञात करे:

Let triangleABC ~ triangleQPR and (ar(triangleABC))/(ar(trianglePQR))=9/16 . If AB=12 cm, BC=6 cm and AC=9 cm then QR is equal to :

Let triangle ABC~ triangle QPR and (ar(triangle ABC))/(ar(triangle PQR))=9//4 . If AB=9 cm, BC=6 cm and AC=12 cm then QR is equal to: माना कि triangle ABC~ triangle QPR और (ar(triangle ABC))/(ar(triangle PQR))=9//4 है| यदि AB=9 cm, BC=6 cm और AC=12 cm है तो QR बराबर है:

Let triangle ABC~ triangle QPR and (ar(triangle ABC))/(ar(triangle PQR))=4/25 . If AB= 12cm, BC=8cm and AC=10cm then QP is equal to:

triangle ABC ~ triangle QRP and AB = 8 cm , BC = 12 cm and AC = 6 cm. If ar(triangle ABC) :ar(triangle PQR) = 16: 25, then RQ is equal to: triangle ABC ~ triangle QRP है और PQ = 6cm, QR = 8cm तथा PR = 10cm है । यदि ar(triangle ABC) : ar (triangle PQR) = 16:25 है, तो RQ ज्ञात करें |

Let triangle ABC~ triangle QPR and (ar(triangle ABC))/(ar(triangle PQR))=1//16 . If AB= 12cm, BC=6cm and AC=9cm then PR is equal to: माना कि triangle ABC~ triangle QPR और (ar(triangle ABC))/(ar(triangle PQR))=1//16 है| यदि AB= 12cm, BC=6cm और AC=9 cm है तो PR बराबर है:

triangle ABC ~ triangle PRQ and PQ = 4 cm, QR = 7 cm and PR = 8 cm. If ar(triangle ABC) :ar(triangle PRQ) = 1 : 4 , then AC is equal to : triangle ABC ~ triangle PRQ है और PQ =4 cm, QR = 7 cm तथा PR = 8 cm है । यदि ar(triangle ABC) :ar(triangle PRQ) = 1 : 4 है, तो AC का मान क्या होगा ?

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