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Harsh made a piggy bank for himself usin...

Harsh made a piggy bank for himself using clay . If the shape of the bank is based on the function f (x)= | x - 4|+ | x - 5 | where f (x) represents the height of the bank

The value of f'(x) at x = 4 is :

A

`-2`

B

1

C

`-1`

D

Not defined

Text Solution

AI Generated Solution

The correct Answer is:
To find the value of \( f'(x) \) at \( x = 4 \) for the function \( f(x) = |x - 4| + |x - 5| \), we will follow these steps: ### Step 1: Understand the function The function \( f(x) = |x - 4| + |x - 5| \) consists of two absolute value terms. We need to analyze how these terms behave around the point \( x = 4 \). **Hint:** Recall that the absolute value function behaves differently depending on whether the expression inside is positive or negative. ### Step 2: Determine the intervals The critical points of the function occur where the expressions inside the absolute values are zero, which are at \( x = 4 \) and \( x = 5 \). We will analyze the function in the intervals: - \( x < 4 \) - \( 4 \leq x < 5 \) - \( x \geq 5 \) **Hint:** Identify the intervals based on the critical points where the behavior of the function changes. ### Step 3: Define the function in each interval 1. For \( x < 4 \): \[ f(x) = -(x - 4) - (x - 5) = -x + 4 - x + 5 = -2x + 9 \] 2. For \( 4 \leq x < 5 \): \[ f(x) = (x - 4) - (x - 5) = x - 4 - x + 5 = 1 \] 3. For \( x \geq 5 \): \[ f(x) = (x - 4) + (x - 5) = x - 4 + x - 5 = 2x - 9 \] **Hint:** Write down the piecewise function based on the intervals you identified. ### Step 4: Find the derivative in each interval 1. For \( x < 4 \): \[ f'(x) = -2 \] 2. For \( 4 \leq x < 5 \): \[ f'(x) = 0 \] 3. For \( x \geq 5 \): \[ f'(x) = 2 \] **Hint:** Differentiate each piece of the piecewise function to find the derivative. ### Step 5: Evaluate \( f'(x) \) at \( x = 4 \) At \( x = 4 \), we are in the interval \( 4 \leq x < 5 \), where \( f'(x) = 0 \). **Hint:** Check which interval \( x = 4 \) falls into to determine the correct derivative value. ### Final Answer The value of \( f'(4) \) is \( 0 \).
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