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If A = [ (0,1,1),(1,0,1),(1,1,0)] then A...

If A = `[ (0,1,1),(1,0,1),(1,1,0)]` then `A^(2) - 3I` =

A

`[ (1,0,0),(0,1,0),(0,0,1)]`

B

`[(1,-1,-1),(-1,1,-1),(-1,-1,1)]`

C

`[(-1,0,0),(0,-1,0),(0,0,-1)]`

D

`[(-1,1,1),(1,-1,1),(1,1,-1)]`

Text Solution

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The correct Answer is:
D
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