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Dimension of magnetic moment is given by...

Dimension of magnetic moment is given by:

A

`[AL^(2)]`

B

`[A^(2)L^(2)]`

C

`[AL^(3)]`

D

Both (a) and (c )

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To find the dimension of magnetic moment, we start with the formula for magnetic moment (M) given by: \[ M = n \cdot i \cdot A \] Where: - \( n \) is the number of turns in the coil (dimensionless), - \( i \) is the current (measured in Amperes, A), - \( A \) is the area of the coil (measured in square meters, m²). ### Step 1: Identify the dimensions of current (i) The dimension of current (i) is given by: \[ [i] = [A] \] Where \( [A] \) represents the dimension of electric current. ### Step 2: Identify the dimensions of area (A) The area (A) of a circular coil is given by: \[ A = \pi r^2 \] The dimension of area is: \[ [A] = [L^2] \] Where \( [L] \) represents the dimension of length. ### Step 3: Combine the dimensions Now, we can combine the dimensions of current and area to find the dimension of magnetic moment: \[ [M] = [n] \cdot [i] \cdot [A] \] Since \( n \) is dimensionless: \[ [M] = [A] \cdot [L^2] \] Substituting the dimensions: \[ [M] = [A] \cdot [L^2] = [A^1 L^2] \] ### Conclusion Thus, the dimension of magnetic moment is: \[ [M] = [A^1 L^2] \] ### Answer The dimension of magnetic moment is given by \( [A^1 L^2] \). ---

To find the dimension of magnetic moment, we start with the formula for magnetic moment (M) given by: \[ M = n \cdot i \cdot A \] Where: - \( n \) is the number of turns in the coil (dimensionless), - \( i \) is the current (measured in Amperes, A), - \( A \) is the area of the coil (measured in square meters, m²). ...
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Knowledge Check

  • Magnetic moment 2.84 BM is given by

    A
    `Cr^(2+)`
    B
    `Co^(2+)`
    C
    `Ni^(2+)`
    D
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  • Magnetic intensity for an axial point due to a short bar magnet of magnetic moment M is given by

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    B
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    D
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    C
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