Ten identical resistance are connected in parallel, each of resistance 10.2 ohm Net resistance will be:

Options

A. `10 Omega`
B. `0.01 Omega`
C. `1 Omega`
D. `0.1 Omega`

Explanation

To find the net resistance of ten identical resistors connected in parallel, we can use the formula for equivalent resistance in parallel circuits. The formula for the equivalent resistance \( R_{eq} \) of \( N \) identical resistors each of resistance \( R \) is given by:

\[ R_{eq} = \frac{R}{N} \]

### Step-by-Step Solution:

1. **Identify the Resistance of Each Resistor**:
Each resistor has a resistance of \( R = 10.2 \, \Omega \).

2. **Identify the Number of Resistors**:
The number of resistors connected in parallel is \( N = 10 \).

3. **Apply the Formula for Equivalent Resistance**:
Substitute the values into the formula:
\[ R_{eq} = \frac{R}{N} = \frac{10.2 \, \Omega}{10} \]

4. **Calculate the Equivalent Resistance**:
Performing the division:
\[ R_{eq} = 1.02 \, \Omega \]

5. **Conclusion**:
The net resistance of the ten identical resistors connected in parallel is \( 1.02 \, \Omega \).

### Final Answer:
The net resistance will be \( 1.02 \, \Omega \).

---