The value of angle of dip at a place where vertical component of earth's magnetic field is `sqrt(3)` times the horizontal component is:

Options

A. `30^(@)`
B. `45^(@)`
C. `60^(@)`
D. `90^(@)`

Explanation

To solve the problem, we need to find the angle of dip (θ) at a place where the vertical component of the Earth's magnetic field (BV) is √3 times the horizontal component (BH).

### Step-by-Step Solution:

1. **Understanding the Relationship**:
The angle of dip (θ) is defined as the angle made by the Earth's magnetic field with the horizontal plane. The relationship between the vertical and horizontal components of the magnetic field can be expressed using the tangent function:
\[ \tan(\theta) = \frac{B_V}{B_H} \]

2. **Substituting the Given Values**:
According to the problem, the vertical component \( B_V \) is given as:
\[ B_V = \sqrt{3} \times B_H \]
Therefore, we can substitute this into the tangent equation:
\[ \tan(\theta) = \frac{B_V}{B_H} = \frac{\sqrt{3} \times B_H}{B_H} \]
This simplifies to:
\[ \tan(\theta) = \sqrt{3} \]

3. **Finding the Angle**:
We know from trigonometric values that:
\[ \tan(60^\circ) = \sqrt{3} \]
Therefore, we can conclude that:
\[ \theta = 60^\circ \]

4. **Final Answer**:
The angle of dip at the given place is:
\[ \theta = 60^\circ \]