Inductor at a high frequency will behave as a :

Options

A. Good conductor
B. Bad conductor
C. Capacitor
D. Inductor only

Explanation

To solve the question regarding how an inductor behaves at high frequency, we can break down the concepts step by step.

### Step 1: Understanding Inductive Reactance
Inductive reactance (X_L) is given by the formula:
\[ X_L = 2 \pi f L \]
where:
- \( X_L \) is the inductive reactance,
- \( f \) is the frequency,
- \( L \) is the inductance.

### Step 2: Analyzing High Frequency
At high frequencies, the value of \( f \) increases. Therefore, as \( f \) increases, the inductive reactance \( X_L \) also increases. This means that the inductor will oppose the change in current more significantly at high frequencies.

### Step 3: Considering Capacitive Reactance
Capacitive reactance (X_C) is given by the formula:
\[ X_C = \frac{1}{2 \pi f C} \]
where:
- \( X_C \) is the capacitive reactance,
- \( C \) is the capacitance.

At high frequencies, as \( f \) increases, the capacitive reactance \( X_C \) decreases. This means that the capacitor will allow more current to pass through.

### Step 4: Behavior of the Inductor
As the frequency increases, the inductor's reactance increases, making it behave more like an open circuit. Conversely, the decreasing capacitive reactance means that the circuit will allow more current to flow through the capacitor.

### Step 5: Conclusion
In high-frequency scenarios, the inductor behaves as if it is in parallel with a capacitor due to the significant increase in inductive reactance and the decrease in capacitive reactance. Therefore, at high frequencies, the inductor will behave like a capacitor.

### Final Answer
The inductor at high frequency will behave as a **capacitor**.

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