Calculate the coulomb force between two electrons separated by `0.8xx10^(-15) m`.

Options

A. 300N
B. 360N
C. 340N
D. 320N

Answer

B

Explanation

According to Coulomb.s law
`F_(e)= k (q_(1)q_(2))/(r^(2)) e^(-) = -1.6 xx 10^(-19)C`
`P^(+) = 1.6 xx 10^(-19)C`
`K= 9 xx 10^(9) Nm^(2)C^(-2)`
`F_(e )= (9xx 10^(9) (-1.6 xx 10^(-19)) xx (1.6 xx 10^(-19)))/((0.8 xx 10^(-15))^(2))`
`=-360N`
`|F_(e)|= 360N`