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The total capacitance if the parallel pl...


The total capacitance if the parallel plate capacitor has n number of interleaved plates, area A and separation d between them,

A

`(epsi _(0) n A)/( d )`

B

`(epsi _(0) A )/( d)`

C

`(epsi _(0) (n -1) A)/( d)`

D

`(epsi _(0) n ^(2)A)/( d)`

Text Solution

Verified by Experts

The correct Answer is:
C
`(epsi _(0) ( n -1) A )/( d)`
For n number of plates in an interleaved capacitor, the total capacitance would be :
`C = (epsi _(0)A)/( d ) ( n -1) = ( n -1) C _(0)`
where, `C _(0) = ( epsi _(0)A)/( d.)` is the capacitance for a single plate and n is the number of interleaved plates.
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