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Electric field intensity at point P due ...

Electric field intensity at point P due to charge distributed over a sphere is:

A

`E = (1)/( 4 pi epsi _(0)) (q)/(r)`

B

`E = ( sigma R ^(2))/( epsi _(0)r ^(2))`

C

`E = (1)/(4 pi epsi _(0)) (q)/(r)`

D

`E =0`

Text Solution

Verified by Experts

The correct Answer is:
B
`E = (sigma R ^(2))/( epsi _(0) r ^(2))`
Electric field intensity due to a point charge distributed over a shapeer is given by
`E _("out") = (1)/( 4pi epsi _(0)) . (q) /(r ^(2)) = ( sigma R ^(2))/( epsi _(0) r ^(2))`
where `sigma ` is surface charge density.
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Knowledge Check

  • Electric intensity at a place due to a charge is

    A
    vector quantity
    B
    scalar quantity
    C
    unitless quantity
    D
    dimensionless quantity

  • Electric field intensity at a point a hollow charged spherical conductor

    A
    is zero
    B
    is constant
    C
    increase with the distance from the centre of the sphere
    D
    none of these

  • Assertion: Electric field intensity at a point due to a positive charge is always opposite in direction to electric field intensity due to negative charge, and it is independent to locațions of charges. Reason: The direction of electric field due to a point charge is away from the positive charge and towards the negative charge along the line joining the point charge and location where the electric field is to be calculated.

    A
    If both assertion and reason are correct and reason is a correct explanation of the assertion .
    B
    If both assertion and reason are correct but reason is not the correct explanation of assertion
    C
    If assertion is correct but reason is incorrect
    D
    If assertion is incorrect but reason is correct.

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