Assertion (A): Resistances connected in parallel has higher equivalent resistance.
Reason (R): `R _(P) = R _(1) + R _(2)+…+ R _(n)`

Options

A. Both (A) and (R) are true and (R) is the correct explanation of (A).
B. Both (A) and (R) are true but (R) is not the correct explanation of (A).
C. (A) is true but (R) is false.
D. (A) is false but (R) is also false.

Explanation

To solve the question, we need to analyze the assertion and the reason provided.

### Step-by-Step Solution:

1. **Understanding the Assertion**:
- The assertion states that "Resistances connected in parallel have higher equivalent resistance."
- This statement is incorrect. When resistances are connected in parallel, the equivalent resistance is always less than the smallest resistance in the network.

2. **Understanding the Reason**:
- The reason provided is the formula for equivalent resistance in parallel:
\[ R_P = R_1 + R_2 + R_3 + ... + R_n \]
- This formula is actually incorrect for parallel resistances. The correct formula for resistances in parallel is:
\[ \frac{1}{R_P} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} + ... + \frac{1}{R_n} \]
- Therefore, the reason is also false.

3. **Conclusion**:
- Since both the assertion and the reason are false, we conclude that the correct answer is:
- Assertion (A) is false.
- Reason (R) is false.

### Final Answer:
The correct option is D: Both Assertion (A) and Reason (R) are false.

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