When the magnification of converging lens is +1, then the image formed is:

Options

A. real inverted and of the same size as that of the object
B. virtual, erect and the same size as that of the object
C. real inverted and bigger than the size of the object
D. virtual erect and bigger than the size of the obect

Explanation

To solve the question regarding the magnification of a converging lens when it is +1, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding Magnification**:
- The magnification (m) of a lens is defined as the ratio of the height of the image (h_i) to the height of the object (h_o). The formula is given by:
\[ m = \frac{h_i}{h_o} \]

2. **Given Magnification**:
- In this case, the magnification is given as +1:
\[ m = +1 \]

3. **Setting Up the Equation**:
- From the magnification formula, we can substitute the given value:
\[ +1 = \frac{h_i}{h_o} \]

4. **Solving for Image Height**:
- Rearranging the equation gives us:
\[ h_i = h_o \]
- This means that the height of the image is equal to the height of the object.

5. **Interpreting the Magnification**:
- A positive magnification indicates that the image is erect (upright) and virtual.
- Since the image height is equal to the object height, the image is the same size as the object.

6. **Conclusion**:
- Therefore, when the magnification of a converging lens is +1, the image formed is virtual, erect, and of the same size as the object.

### Final Answer:
The image formed is virtual, erect, and of the same size as the object.

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