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A wire of length (3)/(2) m is cut into t...

A wire of length `(3)/(2)` m is cut into two parts. If the length of one of the parts of the parts is `(2)/(3)` m, then find the length of other part.

A

`(5)/(6) m`

B

`(6)/(5) m`

C

`(2)/(3) m`

D

`(1)/(6) m`

Text Solution

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The correct Answer is:
To solve the problem, we need to find the length of the other part of the wire after one part has been cut. Here’s the step-by-step solution: 1. **Identify the total length of the wire**: The total length of the wire is given as \( \frac{3}{2} \) meters. 2. **Identify the length of one part**: One part of the wire is given as \( \frac{2}{3} \) meters. 3. **Let the length of the other part be \( x \)**: We can denote the length of the other part as \( x \) meters. 4. **Set up the equation**: Since the total length of the wire is the sum of the lengths of the two parts, we can write the equation: \[ \frac{2}{3} + x = \frac{3}{2} \] 5. **Isolate \( x \)**: To find \( x \), we need to isolate it on one side of the equation. We can do this by subtracting \( \frac{2}{3} \) from both sides: \[ x = \frac{3}{2} - \frac{2}{3} \] 6. **Find a common denominator**: The denominators are 2 and 3. The least common multiple (LCM) of 2 and 3 is 6. We will convert both fractions to have a denominator of 6: \[ \frac{3}{2} = \frac{3 \times 3}{2 \times 3} = \frac{9}{6} \] \[ \frac{2}{3} = \frac{2 \times 2}{3 \times 2} = \frac{4}{6} \] 7. **Subtract the fractions**: Now we can substitute back into our equation: \[ x = \frac{9}{6} - \frac{4}{6} = \frac{9 - 4}{6} = \frac{5}{6} \] 8. **Conclusion**: The length of the other part of the wire is \( \frac{5}{6} \) meters.
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