For the reaction `[Cu(L)_(4)]^(2) + H_(2)O hArr [Cu(L)_(3)H_(2)O]^(2) + I`. The rate of the reaction is given Rate `=-3 xx 10^(-5) {[Cu(L)_(4)]^(2)]} = 3 xx 10^(5) {[Cu(L)_(3) H_(2)O]^(2)} [L]` Hence

Options

A. The rate constant in the forward direction is `3 xx 10^(-5)s^(-1)`
B. The rate constant in the backward reaction is `3 xx 10^(-5) mol^(-1) Ls^(-1)`
C. L is a stronger ligand than `H_(2)O`.
D. From the above data nothing can be predicted.