For a certain reaction log K (S^(-1))= 1...

For a certain reaction `log K (S^(-1))= 14- (1.25 xx 10^(4)K)/(T)` Hence it can be said that
K will be equal to `10^(14)` if

A

T=0

B

`T= oo`

C

T= 1000K

D

T=10K

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