31g of an unknown molecular material is dissolved in 500g of water . The resulting solution freezes at 271.14K . Calculate the molar mass of the material[Given `K_(f) = 1.86 K kg mol^-1` and `T_(f)^(@)` of water = 273K]

(a) Define the following terms : (i) Mole fraction (ii) Ideal solution (b) 15.0 g of an unknown molecular material is dissolved in 450g of water . The resulting solution freezes at -0.34^(@)C . What is the molar mass of the material ? (K_(f) for water = 1.86 K kg mol^(-1))

15.0 g of an unknown molecular material was dissolved in 450 g of water. The reusulting solution was found to freeze at -0.34 .^(@)C . What is the the molar mass of this material. ( K_(f) for water = 1.86 K kg mol^(-1) )

A solution of 1.25g of a certain non-volatile substance in 20g of water freezes at 271.94K. Calculate the molecular mass of the solute (K_(f)=1.86" K kg mol"^(-1)) .

When 45gm solution is dissolved in 600gm water freezing point lower by 2.2K ,calcuate molar mass of solute (K_(f)=1.86 "kg mol"^(-1))